8x^2-96x=256

Solution for 8x^2-96x=256 equation:

8x^2-96x=256

We move all terms to the left:

8x^2-96x-(256)=0

a = 8; b = -96; c = -256;
Δ = b2-4ac
Δ = -962-4·8·(-256)
Δ = 17408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17408}=\sqrt{1024*17}=\sqrt{1024}*\sqrt{17}=32\sqrt{17}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-32\sqrt{17}}{2*8}=\frac{96-32\sqrt{17}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+32\sqrt{17}}{2*8}=\frac{96+32\sqrt{17}}{16}
$